1λ=h/p---------1
and
p2 /2m =K.E=eV-----------2
p=√2meV
frm 1 and 2
λ=h/√2meV
for an electron h/√2me=1.227*10-9
calculate the min wavelength of X-rays emitted by an x-ray tube operating at a tube potential of 40KV??
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9 Answers
1I guess the fol. formula is 2 b used....
eV0 = hc/λmin
but then wat do v take as e as its not an electron its X-rays..
1arey it is electon only!
the electrons come out of the filament ...
travels through the accelerating voltage Vo ..
gets accelerated ... (acc = Ee/m = Vo . e/md)
and then strikes the target! .. from where X-rays come out...
so wat we do exactly is :
equate the energy ...
dat is : energy of the e- = energy of the emiitted photons.
actually whole energy is not used by the photons to come out.
but in case whole energy is used, we get the minimum wavelength.
1hey, can we use √(150/V) ? if i use dis,i get the answer as 0.0612372435696 A°
1wat are these ??
i mean i jus know one formula that madeforiit wrote in his 2nd post...
11oh haan yeh cheez pata tha mereko... but his question was something else...
mereko neend ara ... isiliye ni dikhra :( [13]