what is ref index 4 x<0 nd for shown direction of ray it will go straight through.
An ray of light is incident with grazing angle at (0,0) The refractive index of the medium (in grey) varies with x-coordinate as N=2x. What is the path of the light ray?
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UP 0 DOWN 0 0 9
9 Answers
yeah the fig is wrong... ray must be incident along y axis(almost)
from snell's law 1=μsinθ
=>tanθ=1/√(μ2-1)
dy/dx=1/√(4x2-1)
dy=dx/√(4x2-1)
y=1/2 ln 2x+√(4x2-1)+c
where c is a constant,and its value depends upon where the light enters the region
hey could you please offer a more detailed explanation...because it feel the ray will follow a conic path
because, here angle made by incident ray is just tending to zero(so that light doesn't travels at the boundary of two media) so it is perpendicular to surface hence goes undeviated..
try solving it..
say α→0
sinα.1=sinθ.μ (..μ=2x)
θ is angle angle made with x axis
so dy/dx=tanθ
hence y=0
as α→0
what you are saying may be true if α was a given angle..