Quadratic eqns

If c is positive and 2ax^2 + 3bx +5c=0, does not have any real roots, then prove that 2a-3b+5c>0.

7 Answers

f(-1)>0....
doesnt hav real roots .so must be alwyz +ve or -ve
f(0)>0
hence f(-1)>0...
hence proved

f(0)>0

so f(-1) shud be >0

f(-1)=2a-3b+5c

lolz me late.

If f(0) > 0, then y should f(-1) b also>0??

any*

Thanx....it does look like a parabola!

its a half ellipse!! [3]

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