please answer
A screen is placed at a certain distance from a narrow slit which is illuminated by a parallel beam of monochromatic light of wavelength λ.
if d is the width of the slit,what is the angular width of the central maximum?
(a)sin-1(λ/d)
(b)2sin-1(λ/d)
(c)sin-1(2λ/d)
(d)sin-1(λ/2d)
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7 Answers
Manish Shankar
·2008-12-25 03:59:12
This is single slit difraction pattern
The first minima occurs at path difference of λ
sinθ=θ=λ/d
angular width is sinα=sin2θ=2θ=2λ/d
α=sin-1(2λ/d)
Manish Shankar
·2008-12-25 06:12:28
Sorry...I made a mistake by assuming 2θ to be very small
sinθ=λ/d
so α=2θ
α=2sin-1(λ/d)