wave optics

JEE Mains Tutorials › Optics questions › wave optics

Central fringe of interference pattern produced by light of wavelength 6000A is found to shift to position of 4th dark fringe after glass sheet of refractive index=1.5 is introduced.Find thickness of glass sheet.

#Physics #Optics

UP 0 DOWN 0 0 4
Post on FacebookPost anonymously?

4 Answers

skygirl ·2009-02-27 04:21:07

see, 4th dark fringe =(2X4+1)Î»D/2d = 9Î»D/2d =y

now, Î”x = yd/D

put y value here.

then u will get Î”x.

now this shift is due to the slab ...

shift prodused by slab = Î¼t

equate n get 't' .. :)

UP 0 DOWN 0
Post on FacebookPost anonymously?

theking ·2009-03-03 19:19:52

Didi you are completely wrong
Î”x=(2n-1) Î» /2 =( Î¼ -1)t

which gives t=4.2 Î¼m

UP 0 DOWN 0
Post on FacebookPost anonymously?

skygirl ·2009-03-03 19:28:22

i thnk i took the shift wrong... it will be mu-1.

UP 0 DOWN 0
Post on FacebookPost anonymously?

theking ·2009-03-03 19:41:26

Yes.

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

Close [X]

wave optics

4 Answers

Your Answer

Add Image

Similar Questions