2-methyl propan-2-ol

i have a doubt regarding why does 2-methyl propanol not give the iodoform test inspite of it being a methyl alcohol and how to recognise which methyl alcohol/ oxygen containing compound will not give iodoform test????

6 Answers

39
Pritish Chakraborty ·

The only primary alcohol that gives the haloform test is ethanol and the only aldehyde which gives the test is acetaldehyde.
Being a tertiary alcohol, tert-butanol(2-methylpropan-2-ol) is resistant to oxidation of -OH to =O, is my guess. Wait for more replies.

1
swordfish ·

For any compound to give positive iodoform test, you need this group to be present ( or similar group which can be converted to it by oxidation)-

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2-methyl propanol does not satisfy this condition. Hence it does not give positive iodoform test. Moreover, the only primary alcohol which gives + IF test is ethanol. All secondary alcohols give + test as they can be converted to compound which I showed ( by mild oxidation )

1
redion ·

oh!! now i realise i have typed the compound wrongly and that's why swordfish i might have confused u , sorry , but i have mentioned in my heading that i am talking about 2-methylpropan-2-ol , which definitley containd CH3- C-OH type group and it ain't a primary alcohol , warna kyun puchta????

1
swordfish ·

You wrote 2-methyl propanol and not 2-methyl propan-2-ol.

Anyway, this compound is a tertiary alcohol which does not give positive haloform test.
Think about it this way - can you oxidise it to get a ketone which has the group I showed? Offcourse not.

1
redion ·

so generalising it can we say that acetone which also has has two methyl groups is non oxidisable and cannot respond to iodoform because oxidising it would mean we gotta break c-c bond??? but this is wrong!!! ( and i think after haloform we get sodium salt of acid +haloform rather than ketone!!!! )

1
swordfish ·

You are not understanding what I meant.
I never told if a compound has 2 methyl groups, it cannot respond to iodoform test.
Acetone contains the group I showed, hence it gives +I.F. test.
Did I write any where that we get a ketone after haloform? How did you take it for granted?
For a compound to show +I.F., that group should be present. If you take secondary alcohol, it is first oxidised into a ketone by OI- and then there is an attack by a base.
Refer to a good book for clear understanding.

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