Kinetically II will be hydrated most quickly(no resonance involved). So rate of hydration of II would be maximum. Then with increasing resonance, increasing time is taken. Resonance doesn't occur in I as vinyl carbocation is formed, however unstable.
So (a) is correct...
The correct order of rate of acid catalyzed hydration of following compounds is :
(A) II > I > IV > III
(B) III > I > IV > II
(C) I > III > IV > II
(D) III > IV > II > I
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9 Answers
HOW THE HELL ON EARTH CAN YOU SAY (A) ??? [11]
III provides the benzylic carbocation,,,the most coveted site for hydration and hence it leads the way ! so (d) is definitely correct ! after that you have IV because a hydride shift produces a benzylic carbocation again !
no its D only ........
see
vinylic carbocation is extremely unstable
and the 3 one is extremely stable which leads to very high rate of its formation by le chatekiers priciple , i.e stabler the product more fast will be the forward rxn
are how can A be the ans pritish , it has to be D , if Ea is itself high , then too you are expecting its rate to be faster ??[11]