1
skygirl
·2009-01-23 06:26:39
hey i got the mechanism for the first question !! [1]
jus now posting :)
33
Abhishek Priyam
·2009-01-23 07:00:38
yes... ur right...
as attack of lone pair of oxygen of per acid on carbonyl carbon is not that favoured in ketone..
so deouble bond..
21
tapanmast Vora
·2009-01-23 06:58:31
and ppl. i read in an MTG book....
if there is jus 1 mol CF3CO3H it preferentially attacks da double bond not BVO!!!!
1
skygirl
·2009-01-23 06:46:00
haan yes because the other two are resonance stabilised :)
1
skygirl
·2009-01-23 06:45:23
haan ho sakta hai...
i jus anserewd by seeing the product...
33
Abhishek Priyam
·2009-01-23 06:44:25
in epoxy formation also O* is used..
33
Abhishek Priyam
·2009-01-23 06:43:33
But in mech only one oxygen is used..
wrong product given by him ....
or two moles of per acid was used..
33
Abhishek Priyam
·2009-01-23 06:42:03
its objective time...
just one point to mention in BVO..
CH3-C-O-O*-H
||
O
O* gets inserted... and O of ketone remain at its place so no need of mech now..
1
skygirl
·2009-01-23 06:39:24
he gave that product re ....
1
skygirl
·2009-01-23 06:38:30
if u want the mechanisms i can give...
but if u have, then its fine :)
33
Abhishek Priyam
·2009-01-23 06:37:49
wrong :(
one mole of peroxyacid does only BVO or epoxide formation not both by 1 molecule of peroxyacid..
one peroxyacid gives only one oxygen..
1
aatmanvora
·2009-01-20 10:37:33
ITS BAEYER VILLIGER RCTN DUDE!!!!
1
voldy
·2009-01-21 03:27:34
here are your two diastereomers.
24
eureka123
·2009-01-21 03:21:56
@ srinath, can u give the reason..............ur ans is correct..
24
eureka123
·2009-01-20 10:54:43
some of u may have got it.......still i would be happy to know the mechanism.......
1
°ღ•๓ÑÏ…Î
·2009-01-20 10:49:55
hahahahahhaha popat ho agay
neways org sucks
u post d answer guess we could make out d mch ;)
24
eureka123
·2009-01-20 10:49:01
actually answer is very muich difff........
1
aatmanvora
·2009-01-20 10:44:28
wats da answer to 1 eureka???
is it an epoxide or diol???
3
msp
·2009-01-20 10:44:06
integrations can u explain me how u got the product
3
msp
·2009-01-20 10:40:20
an epoxide will be formed for both the reaction
1
°ღ•๓ÑÏ…Î
·2009-01-20 10:39:30
in bayer villiger we dnt hav a ene