Alkanes

for q4

A)II B)I (ortho effect in II in makes it more acidic in A. In B due to Inductive effect of CH₃ polarity of OH bond decreases making I more acidic.)

C)II D)II (in both cases e^- density above n increases making it more basic.)

For Q4)

As far I have seen, fidelity of ortha effect has always been used to compare the aromatic compound of same composition. i.e, if we are making II in a) more acidic than I, then I should also be of same composition of II.. implies I must also be either p-methyl benzoic acid, or m-methyl benzoic acid.
If Sandipan's answer is followed, then in c) I must have been more basic than II .. see expert's answer here at http://www.goiit.com/posts/list/organic-chemistry-ortho-effect-29780.htm
PS: Yeah, Goiit can be useful sometimes!!..

Do reply the correct explainations.

for q 2 is it c>b>d>a ??

c has 4 hyperconj possibilities also a F with -I so radical is more stble than at b.

4
a 2
b 1
c 1
d 2