1ani markonikov rule is nothing
mk rule moh maya hai use bhool jao
consider stability clearly the ethly side wala carbocation is more stable due to inductive effect
aur yahan SN1 ho raha hai naki SN2 so y consider stearic hinderence
19 Answers
1
1yaaro .. humko laga yeh question itna asaan hai ... but now i think isse difficult question aaya toh fatna tay hai ... [75]
1yeah i know its a bit confusing but inductive is not as weak as we sometimes think
1k 2-3 hyperconjugation is not much of a diff
but in inductive even an extra C can make the difference
so overall ethyl wala carbpcation more stable
13yes v alwaz consider hyperconjugation in such cases
sn1???
106@vishal .. but consider the no. of hyperconjugative hydrogens... it is more if carbocation is formed at methyl side.. and hyperconjugation dominates inductive effect rite?
11why??? there is one H atom on both sides....so no need to consider markovnikov/markonikoff/markoniko rule
So the smaller steric hinderance will make Br go to the carbon to which Me is attached, right?? So why is palani wrong??
1Br will attach to the other carbon having ethyl grp . not the one having methyl grp(ur ans) ... electromeric effect ....
1what u hoped is what u got ! .. sorry wrong ... now the only alternative left is correct ..