1it needds angle of 120* and is having only 60*
pls tell the product...
1. Mg/ ether (excess)
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o-Bromobenzyl bromide ?
2. H2O
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25 Answers
11ok now think if it was not mg/ether in excess. Then which Br will be attacked will be important
11No the answer will be
p-methyl Benzene
Since first it forms a grignard reagent and in G.R mgX have a positive charge
Therefore it will form first carboanium ion and then react with H+
I think this Will be the correct answer1grignard causes a - charge n then since water is there...H+ is taken...simple:0
1then it is rather more easy..just remove the br and put H...i dun think there is any chance of forming a three member ring!!
that was mah post no.8 n i too gave the same product..[:P]
1ok... may be.
i dont know, i thought this should be correct as it was a dihalide.
1i dun think so..i though of dis onen i mentianed in mah previous post that thiswill unstable due to the strain!!though m not very much sure
1u cannot have a alkyne since the strain in d benzene ring will be tooo much then!!
1arre i meant that onnly that it will form grignard wid Mg...n Mg/ether is called grignard reagent!!
1Mg is not grignard. Grignard is RMgX.
with the help of Mg and dry ether along with alkyl halide we form grignard reagent.
1,2 dihalide's rxns give alkenes ( here, 1,2 dihalide alkene type rxn gives alkyne ) with Mg/ether.
1then it is rather more easy..just remove the br and put H...i dun think there is any chance of forming a three member ring!!
1benzoine intermediates reaction doesnt occus...n here if wht u r telling is right shreya then WHY HAVE THEY GIVEN EXCESS GRIGNARD???
