Aryl Halide ( tell product )

ok now think if it was not mg/ether in excess. Then which Br will be attacked will be important

It remains the Same 'Toulene'

No the answer will be
p-methyl Benzene

Since first it forms a grignard reagent and in G.R mgX have a positive charge
Therefore it will form first carboanium ion and then react with H+

then it is rather more easy..just remove the br and put H...i dun think there is any chance of forming a three member ring!!

that was mah post no.8 n i too gave the same product..[:P]

yes.. the answer is correct.

can u pls explain how/why u did it??

u missed ether there in reactant

No...

i dont hve the answer

ok... may be.

i dont know, i thought this should be correct as it was a dihalide.

i dun think so..i though of dis onen i mentianed in mah previous post that thiswill unstable due to the strain!!though m not very much sure

tell if dis is correct

u cannot have a alkyne since the strain in d benzene ring will be tooo much then!!

arre i meant that onnly that it will form grignard wid Mg...n Mg/ether is called grignard reagent!!

Mg is not grignard. Grignard is RMgX.

with the help of Mg and dry ether along with alkyl halide we form grignard reagent.

1,2 dihalide's rxns give alkenes ( here, 1,2 dihalide alkene type rxn gives alkyne ) with Mg/ether.

then it is rather more easy..just remove the br and put H...i dun think there is any chance of forming a three member ring!!

benzoine intermediates reaction doesnt occus...n here if wht u r telling is right shreya then WHY HAVE THEY GIVEN EXCESS GRIGNARD???

it is

ortho bromo benzyl bromide..whts the structure???