1Zn (S)→Zn +2
Cu+2 →Cu
but not sure
Write down the half reactions and cell reaction for Daniel cell.
Zn (S)| Zn+2 (aq) (IM) || Cu+2 (aq) (IM) |Cu(S)
-
UP 0 DOWN 0 0 3
3 Answers
1ya of course sanchit
Zn → Zn2+ + 2e
Cu2+ + 2e → Cu
---------------------------------
Zn + Cu2+ → Zn2+ + Cu
1Here Zn electrode acts as anode while Cu electrode acts as cathode!~ Thus, oxidation occurs at fZn electrode and reduction at the Cu electrode!~
Overall cell rxn wud be
Zn(s) + Cu^2+ ------->Zn^2+ (aq) + Cu(s)