The first one is a Cope rearrangement and the second one seems like a radical reaction...
Mechs in a while...I'm not on the computer but on phone WiFi.
21 Answers
second and third both should be ethene na!! least stable alkene is generally formed
Nah wait...that ain't Cope rearrangement. Those are for 1,5-dienes.
It's a sigmatropic rearrangement even then, a [1,5]-rearrangement to be precise. It follows a six member transition state. Check this for more info : http://www.chemtube3d.com/Sigmatropic4.html
@Vinay : Ring expansion occurs if -
1. Energy is provided
2. The end product is either thermodynamically or kinetically favourable. In this case it is the thermodynamic factor, especially the stability which arises due to aromaticity.
After a nice long nap, I see that qwerty has beaten me to it...bleh :P
Quaternary ammonium hydroxide in which one of the substituent group attached to nitrogen atom has at least one " β " hydrogen when heated , undergoes decomposition to generate an alkene . This is known as " Hoffmann " elimination.
but how do i predict whether the compound will show hoffman elimination or zaitsev elimination?
3 > Same reaction - Final Product -
Only the cyclohexane ring will break and a double bond would come at the carbon atom immediately next to " N + " .
2 > This is Hofmann Elimination obviously . Elimination will take place at " β " carbon . Final product -
" C H3 - C H = C H2 + N ( C H3 ) 3 " .
All three questions look kinda familiar...lol. I'll try these tomorrow after getting back from college.