can u plz explain the ans it will be very helpful for the aspirants here
especially for the second and third term
arrange d molecules in decreasing order of dipole moment.
CH3Cl, CH2Cl2, CHCl3, CCl4
plz explain the solution.
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4 Answers
CH3Cl>CH2Cl2 >CHCl3 >CCl4
here the trick lies in asserting that CHCl3has lesser dipole moment than CH3Cl !!!
let me compare between CH3Cl(1) and CHCl3(2)
the dipole moments in both 1 and 2 are additive(that can be shown by drawing the tetrahedral structures of the two compounds and then finding the directions of bond polarity for each bond). Cl tends to have a ∂- charge due its strong electro negativity and hence in 2 the Cl-Cl repulsion occurs as a result of which the Cl-C-Cl bond angle increases. we know that vector addition involves cos{bond angle}...hence as the bond angle increases the cosine value decreases and as a result the resultant dipole moment decreases !
is it the real reason for which Cl-C-Cl bond angle increases again i am wondering or its that u being so dumb to analyze the facts correctly