shreyan i think ur b is rong.-N3 group will be in the side which experience low steric repulsion.
13 Answers
nops..................
I can give u structure of D if u want...so htat u can work backward..
ya...i had that confusion...
the epoxide has two ways to open...either from low steric hindrance side, or from more stable carbocation forming side..
msp, how can u say that it will depend on the steric factor here??
eureka, is my ans correct till c? (i think not, though) .. and wat is written there from c to d? NaNO2/HCl?
D can be obtained using the concept of PINACOL-PINACOLONE rearrangement !!!!NH2 is preferentially attacked ,here!
It will depend on the steric factor because sodium azide is a small unhindered strong base. It would directly concoct an SN2 reaction. Here's my shot at the question -:
Hey prititsh nice work dude . but I'd like u to be a bit more interested in drawing the e- transfer arrows in a better way .It helps in having clarity otherwise good work :)