LiAlH(O-tBu)3 is hindered and more selective on what it can reduce. It reduces acid chlorides to aldehydes. Then a cyclic ketal is formed, which is more stable than hemiacetals and hence does not form acetals.
3 Answers
Pritish Chakraborty
·2009-10-29 03:29:12
Ankur
·2009-10-30 03:48:47
Pritish is Correct. Ist one is Rosenmund reaction and second one is formation of dioxolane (or dioxalane. ).