this's easy , yet one important thing is hidden rest is routine.
1) 2-pentyne ---------------> (NaNH2) gives A ----------> (methyl chloride) -----------> B -------->(NaNH2) C ---------------->( ethyl chloride)D
the one in the brackets is the reagent added. and A,B,C,D are the intermediates and products.
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yup and further it should not be a problem. :) gud tapan. but it can be a guess also . otherwise , no possibilty of reaction , anyways nice guess. or If you know it good .
NOPES SRI, it wasnt a guess buddy!
1pentyne + KOH --> 2-pentyne........
and its NaNH2 for this one!!! [1]
ANS = 3-Octyne??
common yaar! sum1 confirm the ans man!!!
sorry to say this : I real hate this...... C'mon Dude be responsible enuf to post da answer to a question you wanted the communtiy to solve!!!!
pl. dont get offended!!!
can sum1 else put their solution!!!
(2-Pentyne) H3C-CH2-C ≡ C-CH3 -----(NaNH2)----->(A) H3C-CH2-CH2-C ≡ CH ------(CH3Cl)------->(B) H3C-CH2-CH2-C ≡ C-CH3 ------(NaNH2)---->
(C) H3C-CH2-CH2-CH2-C ≡ CH -------(CH3CH2Cl)------->(D) H3C-CH2-CH2-CH2-C ≡ C-CH2-CH3 (3-Octyne)