IITJEE 2009..questions..

yepp i score a 3 in mah jee 2009..lolz...

ok..here goes d reason..

2 is d correct options...coz for acidity we chek for stability of conjuagte base..
so after H is removed..

3 n 4 give equivalent canonical forms...which is highly stable....so 3,4 >1,2

now 4 has a methyl wid a +I effect from meta position which whill destabilise d carboanion,,,

so 3>4>2>1,,,

1 is a normal form..while 2 has -I effect that will help stabilise d carboanions...

hence..B is d answer...