Say, in phenol, if nitration is carried out, the OH group activates the ring at 3 places. 2 ortho and 1 para. So, why does 47 % ortho nitro phenol form instead of 2/3, ie., 66% ?
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Say, in phenol, if nitration is carried out, the OH group activates the ring at 3 places. 2 ortho and 1 para. So, why does 47 % ortho nitro phenol form instead of 2/3, ie., 66% ?