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Q)In which of these compounds in there no hydrogen bonding?

K2HPO4
K2HPO3
KH2PO3
CH3COOH

What is the procedure for getting the answers?
The structures of these compounds i have not come across in my study so is there any other way of doing it also?

#Chemistry #Organic Chemistry

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4 Answers

Vivek @ Born this Way ·2012-03-30 03:02:55

I guess we need to see which compounds are ionic and which could be covalent.

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Vatika Harlalka ·2012-03-30 03:03:46

Can you explain?

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Vivek @ Born this Way ·2012-03-30 03:11:14

Covalent compounds which will be able to form Hydrogen bonds will have better solubitlity than the corresponding no Hydrogen bonding compounds.

Ionic / Strong electrolytes on the other hand will be soluble due to hydration, there is very less significance of Hydrogen Bonding.

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Aditya Bhutra ·2012-03-30 10:34:08

well you should be able to draw the structures. (only anions are reqd. in the first three)

i think the answer is K₂ (HPO₃)
since hydrogen will be attached to Phosphorus
which is not electronegative enough to show hydrogen bonding.

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Basic Integral Calculus Operators Symbols Matrix Cases

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∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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