All Ch3 groups r on 2nd polyvalent atom in the figure as u may guess using valency of Carbon.I coudnt type it perfectly except in 6..
Which among the following are metamers of molecular formulsA
C4 H10 O.
1-- CH3CH2CH2CH2OH
2-- CH3-CH-CH2-CH3
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OH
3-- CH3-CH-CH2-OH
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CH3
CH3
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4-- CH3-C---OH
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CH3
5-- CH3-O-CH2CH2CH3
6-- CH3-O-CH-CH3 (Here CH3 is with CH)
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CH3
7-- CH3-CH2-O-CH2-CH3
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14 Answers
No answer is 5,6,7
and 5,6 are stated as position isomers...
Can ny1 explain this ans??
Or Uttara is correct??
If he is how??Please help..
R1-G-R2
R3-G-R4
if R1 + R2 = R3 + R4 ( G : functional grp)
then these are called as metamers.
ie. same molecular formula, same G, but structure differ in the no of C on the 2/3 sides of the 'G'.
so here the ans is 5,6,7 only.
Position Isomers are those having same molecular formula, but structures differ in the position of either the G or the multiple bond or the branch along the same main chain.
so ans 5,6 is justified.
pls check all the structures u hve drawn. they are not correct. 2,3 are same and 6,7 also luk same if u write correct no of H atoms.
METAMERISM : The structural isomers which have same functional grp but differ in the
distribution of C atoms b/w diff alkyl groups attached to the functional group
Sorry 1 & 4 r not correct that was a mistake
Ans is 5 6 7
Please explain how can 6 b a metamer of 5 or 7..I can understand 5+7 but hw is 6 a metamer??
Kindly explain..
well,akshant ,,,see option 2....its not matching with d formula
@akshantv5 : I gave the definition for metamerism
That explains 6 is also a metamer due to the distribution of alkyl groups attached to the functional group
@ UttaraKindly explain why 1 & 2 r not metamers..Arent there also alkyl groups distributed??
No akshantv5 in 1 & 2 alkyl groups r not distributed around OH (I mean either side)
Ex CH3CH2CH2NH2 - CH3CH2NHCH3 - N(CH3)3 R METAMERS