No answer is 5,6,7
and 5,6 are stated as position isomers...
Can ny1 explain this ans??
Or Uttara is correct??
If he is how??Please help..
Which among the following are metamers of molecular formulsA
C4 H10 O.
1-- CH3CH2CH2CH2OH
2-- CH3-CH-CH2-CH3
|
OH
3-- CH3-CH-CH2-OH
|
CH3
CH3
|
4-- CH3-C---OH
|
CH3
5-- CH3-O-CH2CH2CH3
6-- CH3-O-CH-CH3 (Here CH3 is with CH)
|
CH3
7-- CH3-CH2-O-CH2-CH3
All Ch3 groups r on 2nd polyvalent atom in the figure as u may guess using valency of Carbon.I coudnt type it perfectly except in 6..
No answer is 5,6,7
and 5,6 are stated as position isomers...
Can ny1 explain this ans??
Or Uttara is correct??
If he is how??Please help..
R1-G-R2
R3-G-R4
if R1 + R2 = R3 + R4 ( G : functional grp)
then these are called as metamers.
ie. same molecular formula, same G, but structure differ in the no of C on the 2/3 sides of the 'G'.
so here the ans is 5,6,7 only.
Position Isomers are those having same molecular formula, but structures differ in the position of either the G or the multiple bond or the branch along the same main chain.
so ans 5,6 is justified.
pls check all the structures u hve drawn. they are not correct. 2,3 are same and 6,7 also luk same if u write correct no of H atoms.
METAMERISM : The structural isomers which have same functional grp but differ in the
distribution of C atoms b/w diff alkyl groups attached to the functional group
Sorry 1 & 4 r not correct that was a mistake
Ans is 5 6 7
Please explain how can 6 b a metamer of 5 or 7..I can understand 5+7 but hw is 6 a metamer??
Kindly explain..
well,akshant ,,,see option 2....its not matching with d formula
@akshantv5 : I gave the definition for metamerism
That explains 6 is also a metamer due to the distribution of alkyl groups attached to the functional group
@ UttaraKindly explain why 1 & 2 r not metamers..Arent there also alkyl groups distributed??
No akshantv5 in 1 & 2 alkyl groups r not distributed around OH (I mean either side)
Ex CH3CH2CH2NH2 - CH3CH2NHCH3 - N(CH3)3 R METAMERS