MTG Doubt

An unknown alcohol gives blue ppt. in Victor Meyer's test.The no. of alpha H atoms in alcohol are ___ ?

They gave the ans as 1,,saying R2CH-OH has one alpha H .. they have taken the underlined carbon to be alpha carbon,,but that is not alpha carbon right ??

9 Answers

13
Avik ·

One of the major confusions...sometimes they take the functional carbon as alpha (remember the Beta-Elimination during Dehydrohalogenation??),
n sometimes the carbon nxt 2 the functional carbon as alpha (as in alpha-beta unsaturation etc.)...

Even i'm confused here...

1
Ankur ·

arrey.. sahi to hai.. alpha carbon is the carbon directly attached to functional group. Here fx group: OH . alpha H : R2 CH OH . Whats wrong in that?

1
cipher1729 ·

think its correct dude

11
Gone.. ·

no alpha carbon is carbon attached to carbon attached to func gr.

1
Ankur Loonia ·

arre i think that's in the case of carboxlic acidis. the ans. given in the buk is correct with respect to alcohols

39
Pritish Chakraborty ·

Its absolutely fine. Secondary alcohols give blue coloration in Victor-Meyer's test, and the alpha carbon is the carbon attached to the functional group here. The Greek numbering is a relative system. It depends relative to WHAT we are numbering the chain. Here it is relative to the -OH group.

11
Gone.. ·

Pritish what your saying is what writers like Morrison n Boyd say,,what i am saying,writer like Finar and Solomon follow..this is an everlasting confusion,,for this q is best to go for ans as 1.

13
Avik ·

Ohk..... something clicked at last......

The Alpha Carbon is the 1st Carbon directly attached to the Functional Group.

So if -OH is the func. group, then the 1st carbon will do the job.......

But when v have a compound like this- RCH2CH2COOH, the alpha corbon is the underlined one (Kyunki func. group is COOH & the CH2 carbon is the 1st carbon attached directly to it)

P.S. I now realise tht Ankur was saying the same thing, though i didn't get it at tht time... :p

11
Gone.. ·

ya it will be like that only then. [1]

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