one for the bigshots...

CH₃CH=CH₂ + CCl₄ in presence of peroxide......

and another 1 wid d same substrate in presence of hv

35 Answers

[4][1]

yes madame sky ur absolutely ryt......

gimme ur exlaination...fter ccl4 breaks cl and ccl3 radicals then how do v decide wich is gonna attack 1st

CCL3 attacks first ... and develops a second deg woh cheez.. kya kehte bhool gayi :P

haan yaad aya free radical..

dat will form...

waha pe Cl will go and attach...

but how do u noe dt ...

ny logic or is it sumthin dt has to b kept in mind as a fact..?

[2][2][2][2]

arrey but y dont we req both uv and peroxide sirf peroxide se kyun kaam chal jayega

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