this might be silly bt this is my dbt..
suppose an optically active substrate undergoes a reaction such that the configuration is retained i.e. no bonds of the chiral atom is broken
now is this true that if an (S)(+) is reacting then the compound formed is always either a (S)(-) or a (R)(+)
examples: 1) (S)-(-)-2-Methyl-1-butanol forms (S)-(+)-2-Methyl-1-butanoic acid
2) (S)-(-)-2-Methyl-1-butanol forms (S)-(+)-1-Chloro-2-methylbutane
concurring doubt...
what is formed wen (S)-(+)-sec-Butylchloride reacts with Cl2 in presence of light..
is it
a) (R)-(+)-1,2-Dichlorobutane or,
b) (R)-(-)-1,2-Dichlorobutane???
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1 Answers
1is it 1,2 dichlorobutane or 2,3 dichlorobutane??????
becoz secondary radical is more stable dan primary.....
well, optical rotation (+ or -) is pure experimental....we can't predict de rotation.......
