org,,,8ques

Q1) SO₃H ??? may be because it has highest preference among functional grps.
Q3) FeCl₃ gives neutral soln. in water

Q5) Toluene reacts as a normal aromatic hydrocarbon towards electrophilic aromatic substitution.] The methyl group makes it around 25 times more reactive than benzene in such reactions. It undergoes smooth sulfonation to give p-toluenesulfonic acid, and chlorination by Cl2 in the presence of FeCl3 to give ortho and para isomers of chlorotoluene. It undergoes nitration to give ortho and para nitrotoluene isomers, but if heated it can give dinitrotoluene and

ultimately the explosive trinitrotoluene (TNT).

1. A (order is NR3⁺>NO2⁺ and then the rest)
2. D
3. A (strong base and strong acid give neutral soln)
4. A?
8. D

@manmay
ans1 rite,,rest wrong
explain 1st plz

@asish
ans1 wrong
rest all rite

but can u explain 4,8 ??

and in 2 will nitrobenzene be good starting compound though it is highly deactivating ??

It will be BF₃ for Q4. The alkene's double bond acts as a nucleophile, donates electrons into boron's vacant orbitals(lewis acid action). This complex then acts as electrophile and attacks benzene, and when aromaticity is regained BF₃ leaves.

In Q8, the para isomer of di-chlorobenzene has highest melting point because it fits best into its crystal lattice. Lattice energy is quite high and subsequently so is the melting point(as compound is more stable).

eure for Q2 have they given how many steps maximum or something? Because otherwise d) is the best option. We are only chlorinating once. If we try again it won't work as both chlorine and nitro groups are deactivating.

Q1) i wrote it on basis of priority of functional groups which is highest for sulphonic acid( -SO₃H )group.

if my Q5) is rong then other ans. should be o- ,p- noitro toluene becoz may be dil. HNO₃ i didn't see it was dilute.

Ans1

So according to this NO₂ shud be the answer..

Q7 product will be bromobenzene