i think it is d)
which one of the resonating structures of 1-methoxy-1,3-butadiene is least stable :
_ +
a)CH2-CH=CH-CH=O-CH3
_ +
b)CH2=CH-CH-CH=O-CH3
_ +
c)CH2-CH-CH=CH-O-CH3
_ +
d)CH2=CH-CH-CH-O-CH3
explain the reason
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8 Answers
seems B to me, bcoz of increased charge separation.
a is most stable!!
i think c
bornidentity a,b will be stable than c,d since octet of each atom is complete
ohh i forgot to take into account octet consideration....compared to (c,d ) (a,b) will be more stable , and among (c,d) c will be least stable becoz in c -ve charge is on sp3 carbon, while in d -ve charge is on sp2 carbon, which would be more stable.
hence C will be least stable.
obviously on Oxygen in the first 2 options , octet of C is complete, how can there be +ve