Organic Crackers -II

:: Some Conversions ::

1) BromoBenzene -----> 4-MethoxyPhenol (Max. 5 steps)

2) NitroBenzene -----> Meta-nitroPhenol (Max. 4 steps)

3) BenzoicAcid ------> MetaFluoro BenzoicAcid (Max. 3 steps)

:: One Simple Qn ::

4)

9 Answers

39
Pritish Chakraborty ·

1)
Bromobenzene -----(Dow's process)--> Phenol.
Phenol + Cl2/FeCl3 ---> para-chlorophenol
Para-chlorophenol ---(Dow's process)--> 4-hydroxyphenol
4-hydroxyphenol + Sodium/Sodium chloride --> 4-methoxyphenol

2)
Nitrobenzene + conc HNO3/conc H2SO4 --->
Dinitrobenzene (meta position)

Dinitrobenzene + (NH4)2S ----> m-nitro aniline

m-nitroaniline + NaNO2/HCl ---> Diazonium salt

Diazonium salt + H2O/warm ---> m-nitrophenol

13
Avik ·

1) Dow's process gives low yield naa & takes place in drastic conditions ? Isn't there a better alternative to insert -OH in the ring (frm a halide, apart frm the diazonium one) ?

2) [1] Bahut sahi!

39
Pritish Chakraborty ·

There are 5 methods to prepare a phenol....Cumene-hydroperoxide method, Dow's process, Diazonium salt method, from benzene sulphonates, and from salicylic acids. The one involving a halide directly attached to benzene ring is Dow's process..you may say yield is low because it follows benzyne mechanism. The other way to kick a halide out is the SNAr pathway, involving electron withdrawing groups...here you go.

Chlorobenzene + Cl2/FeCl3 ---> para-dichlorobenzene

Para-dichlorobenzene + conc HNO3 ---> Nitration at ortho positions.

1,4-dichloro-2,6-dinitrobenzene + sodium methoxide(1 mol) ---> 4-methoxy-2,6-dinitro-chlorobenzene (since NO2 groups make benzene acidic, it easily undergoes the nucleophilic substitution reaction)

4-methoxy-2,6-dinitro-chlorobenzene + conc NaOH(1 mol) ---> 4-methoxy-2,6-dinitrophenol (Again SNAr)

4-methoxy-2,6-dinitrophenol + Sn/HCl + NaNO2/HCl + H3PO2 ---> 4-methoxyphenol (Diazonium salt formation and reduction)

39
Pritish Chakraborty ·

Third one is by Schiemann reaction.

Benzoic acid + conc HNO3/conc H2SO4 --> m-nitrobenzoic acid

m-nitrobenzoic acid + Sn/HCl ---> m-aminobenzoic acid.

m-aminobenzoic acid + HBF4/NaNO2 ---> m-fluorobenzoic acid (Schiemann reaction)

13
Avik ·

Thnx Pritish [1]

Noone trying out 4)th,,, easy hai. (Not my doubt though)

39
Pritish Chakraborty ·

Is it a bromide salt?

106
Asish Mahapatra ·

4. Sulphuric acid

1
pranav ·

pritsh = organic boss at tarhet iit !!! is nt it??

13
Avik ·

Rite there, asish. [1]

Your Answer

Close [X]