11
Khyati
·2010-10-08 09:11:10
2)Provide an explanation for the fact that all trans-1,2,3,4,5,6-Hexaisopropylcyclohexane is a stable molecule in which all isopropyl groups are axial.
Ans:- The shape of the isopropyl group is such that it fits more readily, and consequently with less steric interaction, when all the groups are axial.
11
Khyati
·2010-10-18 17:41:49
dbt cleared, thanks to qwerty [1]
11
Khyati
·2010-10-18 10:43:31
Is 2- Bromobicyclo[1.1.0]butane capable of existing as enantiomer?
I drew its structure and I think it is capable of forming enantiomer because 2 carbons (upper and below one) has 4 different groups attcahed.
just clear my doubt
11
Khyati
·2010-10-14 21:22:31
Maximum enolisation ka ek question tha, but I wanted to know the reason, because of this reason I can now solve other problem related to that. [1]
Thanks Prats [3][1]
39
Pritish Chakraborty
·2010-10-14 13:32:05
o-nitrophenol is most volatile because of chelate formation due to H-bonding(between oxygen of -NO2 and H of -OH).
Maximum enolisation? Any specific situation or is this a general question? The enol form is preferred if there is some stabilizing factor which gives greater stability than if the compound were present in keto form, for eg - aromaticity.
11
Khyati
·2010-10-14 09:21:46
Some more questions
a)What is the condition for the maximum enolisation to take place?
b)Which is most volatile isomer of nitrophenol ? why?
11
Khyati
·2010-10-09 11:04:00
Thanks Pritish, I got the explanation now. Nice images
39
Pritish Chakraborty
·2010-10-08 10:54:06
Khyati, this image may help you to gauge the explanation of question 2 -:
And you've asked Q1 around in other forums also. I posted something similar on why elimination is favoured at higher temperatures...if I find the link of the thread I'll paste it here.
11
Khyati
·2010-10-02 08:56:08
Where are you Pritish? Please help me out in organic [2]
11
Khyati
·2010-10-04 20:41:00
Wow Qwerty, kya mast explanation diya hai. Thanks a lot [1]
23
qwerty
·2010-10-04 19:24:39
remove all possible H, and then check the conjugate bases for each H.
the most stable base will result frm most acidic H.wat venkatesh said is correct , but only when all other important factors arent present.
but in a cyclopentadiene, resonance is possible. now when the H from sp3 carbon will be removed , we get a planar comp with 6 delocalised π electrons . hence the resulting anion is aromatic , which makes it highly stable.
11
Khyati
·2010-10-04 10:01:01
Arey but in the answer they have given the hydrogen attached to sp3 carbon acidic
See the arihant organic chemistry textbook, page no. 16 question no.4 (b) and (c)
1
Abhisek
·2010-10-04 10:00:52
Ans 4:
The dotted lines show hydrogen bonds....
1
venkateshan
·2010-10-04 09:53:31
the H attached to the sp hybridized atom is more acidic than sp2 hybridized and sp3 hybridized....
Acidic order :
sp H > sp2 H > sp3 H
11
Khyati
·2010-10-04 09:47:22
Some more questions
3) How to know the acidic hydrogen in the compounds in which hydrogen is attached to the atom other than oxygen, for example in Cyclopent-1,3-diene?
4)Why only 4 water molecules are directly attached to one water molecule? I know its a stupid question, but I cannot think of a reason for it.
11
jeetopper jee
·2010-10-03 22:16:58
@khyati yup the reason given by you is perfectly right.i asked it from a senior
11
Khyati
·2010-10-03 07:31:15
1)Why can the use of high temperatures in the catalytic hydrogenation of alkenes to alkanes be self-defeating ?
ΔG = ΔH - TΔS
Because the higher the temperature, the more likely a dehydrogenation back to the alkene will take place!
http://www.chemicalforums.com/index.php?topic=43918.0