Waise, success magnet mein bahut answers wrong hote hain naa...i've heard. [4]
Q1. The weakest base among the following is:
(a) amines (b) Amides (c) Ketones (d) Nitriles
more will be added after this question gets answerd
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aieeee, if the solvent is protic, comparing between O and S, S having larger size will tear more easily through the envelope of protic molecules surrounding it. This is similar to order F < Cl < Br < I in protic solvents because I has largest size.
S has to be the more nucleophilic atom.
When we compare different nucleophiles in which nucleophilic atom is same(here it is O-), nucleophilicity order will follow basicity order. Thus the order I have mentioned.
How does a protic solvent make a larger molecule less nucleophilic??? Balki oxygen atoms will attract more protic solvent molecules towards itself and find it harder to tear through that envelope because of its smaller size.
1) lets see which among the following is least stable after addition of H+ ion :
a) R-NH3+ is stable as electron releasing group R stabilises the positive charge.
b) R-C+-OH-NH2 is also stable as lone pairs of O and N stabilise the +ve charge.
c) R-C+-OH-R is also stable as the two alkyl groups stabilise the positive charge.
d) R-C+=NH , a vinylic type structure is formed which is unstable.
Thus , nitriles are least basic.
First of all , the medium is aqueous i.e. protic solvent (H2O)
Its obvious that CH3OH is the least nucleophilic , while CH3S- is the next one as its the larger molecule than rest. thus , a protic solvent makes a larger molecule less nucleophilic.
now , from the rest three , THE BASICITY ORDER hs to be first found out.
carboxylate ion < phenoxide ion < hydroxide ion
NOTE : If the solvent is protic , then the basicity and nucleophilicity are inversely related
thus, the nucleophilicity order is : carboxylate ion > phenoxide ion > hydroxide ion
so, the order goes as : carboxylate ion > phenoxide ion > hydroxide ion > CH3S- > methanol
not sure...
it was aieeee's doubt....
he says this is the order given in Bruice which he feels is wrong
Q5 - Main concept : If the nucleophilic atoms in different molecules are the same, nucleophilicity order follows basicity order. You can compare phenoxide, carboxylate, etc that way. Methyl sulfide anion will be strongest nucleophile I guess...
For the others, add a proton to compare.
I - CH3O+H2
II - Phenol
III - Carboxylic acid
IV - H2O
From these, it is clear I is the most acidic, it can give a proton up most easily. Following next is phenol, as phenoxide ion is heavily stabilised by resonance. Then comes carboxylic acid, which is lightly stabilised by resonance. Water is the weakest acid here.
So acidity order is -:
I > II > III > IV
Basicity order will be ulta
IV > III > II > I
So the actual order is CH3S- > OH- > Carboxylate > Phenoxide > Methyl alcohol
This order is also verified by the fact that methyl alcohol has no formal charge on it and is hence the weakest base.
Sulphur is more nucleophilic here because of its larger size which allows it to tear more easily through the envelope of water molecules present in solvent, which surround it.
@asish..
But NCERT also says Inversion. btw, where's the Qn frm ?
@ishan.. arrey but u said naa ki "hence it is more basic as the electron density is max incase of nitriles" ...
but in ans it was given
(retention product major and inversion product minor)
Q2. Which of the following will respond to iodoform test?
(a) CH3COCH2COOC2H5
(b) CH3COCH2-C6H5
(c) ICH2COCH2CH3
(d) all
Q3. cis-2-butene + HCOOOH ----> I
trans-2-butene + HCOOOH ----> II
then give the stereochemical str of the products (i.e. racemic mix or meso product)
Q4. subsitution/elimination with aq KOH prefers
(a) SN1 (b) SN2 (c) E1 (d) E2
Q5. Arrange the order of nucleophilicity of the reactants in aqueous medium
1-CH3OH
2-Phenoxide ion
3- carboxylate ion
4- CH3S-
5- OH-
No idea about the dominating business,,, this is the only reason i can think of (on seeing the answer).
but then in amides there is delocalisation and sp2 hybridisation.. So which will dominate and more importantly WHY?
Okay, because "N" in nitrile is "sp" hybridised, 50% s-character, so donation of lp is very unlikely.