look boron is more electropositive than hydrogen so B having some positive charge density attacks on the pie electron density and makes a co-ordinate bond then elongated bond of boron and hydrogen attacks the carbonium ion in this case rearrange ment products are not possible because h can attack on alpha carbon atom only as boron hydrogen bond is not broken
now that we know that Hydroboration oxdn doesn't cater for steric hinderanxe her's a soln of atest of this site Q1 what will be the final product after adding 1.BH3 / T.H.F 2.H2O2 /0H-1Your Answer:
Correct Answer: Score: -5 Explaination : due to stearic hindrance BH2 will approach from less hindered site and OH will be attached there..!!
What do u say know!!!!
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it's concerted try yourself and post da . this hint should suffice. try.
sry I'm very lazy :( .
in this process the boron atom will adds to the carbon with least steric hinderance
the ans will be 2 methyl cyclo pentanol.can u guess the reason from the ans from this
ok guys please give the mech for hydroboration of 1 methyl penetene.please ans this question. i think it may give idea abt the mech
thank u gagar sn nishant bhaiya for ur views but i still can't understand what feenyx_21 wants to deduce
thats very true feenyx_21 but idid'nt get what u want to say about the question
Hey Guys..
according to the mecahnism of Hydro-Boration oxidation the oh- adds along the double bonded carbon atom which is less substituted..You may assume that it s similar to anti markonikoff's addition in halides..
Ex:- on hydro boration oxidation gives
and not
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yes gaurav and abhsiek... there is a mechanism in place..
whenever users point out errors, we do fix them...
we must have been pointed out a lot of errors by our users.. we always make sure that we fix those.. :)
i think there must be a provision of rechecking in case of wrong solution and these things needs to be discussed