23The first intermediate will be C (OH) Cl3
wich itself is unstable ( OH and CL on same carbon ) and gives (Cl)2C=O wich further gives K2CO3
btw ans kya diya hai
CCl4 + KOH (excess) ------> end product of reaction is
(a) K2CO3.
(b) C02.
(c) C(OH)4.
(d) HCOOK.
sholdnt the answer be CO2...??
as the 1st product( the intermiate) formed should be C(OH)4..
THEN FROM IT THERE WOULD BE 2 MOLES OF WATER BEING ELIMINATED.... AS THERE ARE 4 (-OH) GROUPS ON THE SAME CARBON..
thus the end product should be CO2.
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3 Answers
231yup first intermediate will be C(OH) Cl3 but after that, slight heting will give Dichlorocarbene, it will be unstable, readily attacked by OH`, to form (Cl)C=0 which will then remove Cl for OH and form potassium formate , what is answer???