Nops ans given is (II) [2]
To prepare anisole, which is the best path :-
It can't be the first one bcoz c -Br bond is stable due to resonance hence nucleophilic attack is not preferred. But what abt the second and third reactions ?????
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10 Answers
sorry din see the benzene rings first you had drawn cyclohexane..
eureka: its not such a bulky nucleophile..
Benzyl halides react very easily through SN1 and SN2... they have the same characters as primary and secondary alkyl substrates (atleast thats wats ritten in Morrison Boyd)
benzene has a planar structure,so it can react with the electrophile of nucleophiles on both the sides of the molecule,bulky in the sense means that the space occupid in the 3dimensions is large.And i read in arihant that the tendency for a phenyl and methyl to get shifted to adjacent positions were the same,This will not be true if benzene is a bulky molecule.
tush is there nething more given for reaction 3
And as far as i know dat diazomethane attacks the electrophilic site of the compound,So if it attacks the electrophilic site then the resultant compound will not be anisole.Chemists use diazomethane as a methylating agent.
@ msp
Nothing more was given abt reacn 3 [2]
This ques is frm Arihant only
definitely, I and III cannot be the answers because for I , the partial bond character in the C-X bond is very strong !
1st can't be the answer
3 rd one gives anisole with CH2N2 but as alcohols are weak acids and requires a catalyst badly to increase thier acidity(in the presence of HBF4) ....... ......
so 2 nd one is the answer[1]