sn1 or sn2

ch3-ch(Br)-ch3 [in presence of OH-(aq)] -------->

above reaction is sn1/sn2>>>>>

i think it must be sn1 as a polar protic solvent is there........am i right???

1 Answers

It is 2Â° and forms CH₃-CH(OH)-CH₃

But I think it should form a racemic mixture.

My reasoning:

In both S_N1 and S_N2, 2Â° halides have middle reactivity preference.

But in S_N1 the order of reactivity is F>Cl>Br>I if i am not wrong, whereas it is the opposite in S_N2.

Since the halide is of bromine, S_N2 would take place, but due to presence of polar protic solvent, S_N1 would also take place.

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