sn2

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out of c6h5br n c(me)3br
compare rate of sn2

#Chemistry #Organic Chemistry

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6 Answers

1

Anurag Khandelwal ·2009-02-17 00:33:18

C6H5Br does not undergo SN2... it undergoes substitution by benzyne mechanism.
So C(Me)3Br>>>>>>>>>>>>>>C6H5Br for SN2!!

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Dr.House ·2009-02-17 00:34:56

c(me)3br forms a 3 degree cation na. so why will it take part in sn2 leaving sn1?

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Anurag Khandelwal ·2009-02-17 00:36:17

Then neither pf them undergoes SN2...

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Dr.House ·2009-02-17 00:39:32

thats what. i am not able to get the sense of the question.

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msp ·2009-02-17 00:53:20

no it is not the meaning the 3 degree cation can undergo SN2 rxn but veryveryveryveryveryveryveryveryveryveryvery less da

but if u compare this qn the ans would be like c(me)3-br>phbr.

becos in SN2 rxn back side attack is one of the step.this is impossible in phbr

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vector ·2009-02-17 01:09:17

thanks

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