106ans given as first one.. seen this ques in two reliable sources so posted even had thot II
13 Answers
106
19ANS 1> carbocation I is more stable than II because the inductive effect of ethyl+ethyl> methyl+propyl
11@ Debo, but the order for stability is:-
Mesomeric effect > conjugation > Hyper conjugation > I effect ????
106yeah debo.. can u explain why. it is III>II>I
further in first question
the second one has 4-hyperconjugative H naa instead of 5 in first so why second one?
as said by tush .. Hyperconjugation> Inductive
1yeah for q1) a is the correct answer as in this case inductive overpowers hyperconjugation!!!!!!an exception....some authors also call it "stability due to symmetry"god knows what that is!!!!
1sn2 mechanism genarly ocuur where there is no intermideate formed
and when tertiary carbocation formed sn1 i prefered.
but when secondray carbocation is forming as an intermidiate then whether there is substituion or elimination on carbon atom is decided by thermodynamic and kinetitics factor eg.temperature
if temp is increased ther will be elimination and alkene s formed and if substitution then neucliphile come on carbon atom and prevents frmation of alkene.
is this statement true or false ?
1ii is more stable than i in ques 1
due to hyperconjugation which has more efecct then inductive effect
1in the first question inductive effect will be same for both but due to hyperconjugation 1>2
in the second question the order is: 1>2>3
reason: all three are 1degree carbocation however on basis of hyperconjugation 1>2>3
do not confuse urself with the comparison of CH3CH2 I effect whith
hyperconjugation effect because hyperconjugation overpowers I effect in case of carbocation