STABILITY PROBLEM 2

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Arrange in order of stability giving reason.

Ans : I < IV< II < III

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govind ·2010-03-29 10:07:56

Same case here try arranging using carbocation stability...sp³ hybridised free radical is more stable than sp²..so I is least stable..now there is conjugation in II and III but in III we have tertiary radical so it is more stable..
IV is just a primary free radical
so the order is
I < IV < II < III

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STABILITY PROBLEM 2

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