29
govind
·2010-03-29 09:57:23
Yaar this question has been discussed here b4 also..see the stability of free radical is the same as the stability of carboaction..so sp3 hybridised free radical is more stable than sp2 hybridised..
so V and III least stable
I is just simple free radical
Now we have conjugation in IV and II and IV is more conjugated then II
so order is
V < III < I < II < IV
1
Grandmaster
·2010-03-29 10:01:41
i agree with govind and now comparing I with V.....I is just a normal free radical which has high energy but 5 is like an aryl system which is highly unstable!!!!!
1
Bicchuram Aveek
·2010-04-02 10:11:21
Govind can you please tell me why V<III and not III<V ?
1
sriraghav
·2010-04-02 10:17:25
In V the aromaticity is disturbed....whereas not in III
1
The Enlightened One - jsg
·2010-04-02 11:00:43
see ,
V is antiaromatic while III is non aromatic...by aromaticity concept Stability of non aromatic > stability anti aromatic..