sve

is B correct?

Ans : B

Reason : Flip the structures II & III.(While flipping remember axial posn changes to equatorial.) Now, stability is more if heavier grp. is in the equatorial posn.

The order of stability should in fact be : III~>II>I>IV

Hence the ans closest to this is B

okok
but dont do dis logik in iit
mayb v hav 2 consider wequatorial vonformation gr8ly
n then other one not much
n since 2 r halogens , ess reactive than cl n f
then tey r ~~
but if F OR cl , then not~~
thween mayb
F would me least stable but after the other two equatorial ?
i m ckrt or wrong ?

uffo see d options dude....................

symmetry in d OPTIONS................

this is wat u wrote
look at B and D the first two are same
now see A and B the last two are same

so common one is B

ans is B
though b n d r same ........in 1st 2
where last 2 same in a n b ?

ajin see post num 11.....by symmetry i meant symmetry in d options

br is more -negatrive than iodo
n iodo is bigger than bromo ?
then wats same ? betn thwem ?

i told my explanation........

if concept doesnt work.....apply symmetry thts all

I GOT THAT
4 < 1
just i didnt was
how 2 ~~~~3
?

i hav uploaded image but y is it not visible ?
its jpeg image ? will it work ?

YUPPPPPP
ITS
B ?
HOW N Y ?

look at B and D the first two are same
now see A and B the last two are same

so common one is B

ans is B

then its B.....................

ill tel my logic w8

i think itz B)..........

not c
fm A , B , D ?
WATSIT ?

i only thought C
BUT ITS NOT !
U KNOW Y ?
anymore guesses !
tell me right logik n iw ill tell u rite answer !

coz I^- is a good leavin group so III will be least stable

is it C??