1I guess. Basically, as I understand it, the more # of alternating double and single bonds, the merrier. And you want the free radical to be on a single bonded carbon.
here below i list the thngs i learnt in org in t iit...correct me if i am wrng
1) conjugation imlies... pi sigma pi sigma
or, pi sigma free elec sigma pi...
or, pi sigma - sigma pi.. when - is on a C atom
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1there cud be carbocations also n lone pairs if the element is not carbon
1Its a separate huge chapter..Carbocations. You would have to read about it. Comes with tons of different types of reactions.
1Adding to the list, dont forget the electron donating vs withdrawing thing, which determines which H will be removed.
49ohh god u r speaking hebrew.......speak simple and try to illustrate wid diagrams if u can....[2][2]
1OK Carbocations---cannot be explained. U have to first read theory somewhere.
As for electron donating:
Certain groups of atoms have a tendency to withdraw electrons, or in other words, donate protons. And certain other groups have tendency to donate electrons, or in other words, withdraw protons. So if you think about it, a system with EDG (e donating group) will stabilize positively charged carbons. And conversely a system with EWG will stabilize anions.
Now going back to the problem u had in the other thread about which hydrogen will be removed, there were 2 possibilities, basically 2 carbons from which u could remove hydrogen.
1 carbon was a methyl and the other was simply triple bonded to another carbon. Now, Alkane groups are EDG. so they donate e,lectrons, or in otherwords, withdraw protons. But you want to REMOVE a proton from this structure. therefore, it is easier to do with from th other C.
29@Subho..u may read Peter Sykes..it's a really good book for beginners..It's available in e-book format...