I wanna know what happens when a Grignard reacts with a carboxylic acid. does it just take the O of the OH bond? or does it attack the compound like it attacks aldehydes and keetons?
1it attacks the compound like it does in case of aldehydes and after that the OH-grp leaves compound forming a ketone(except in a case of formic acid where it forms an aldehyde)....then another grignard reagent attacks....in a similar way....after that when we add water to it,an alcohol is obtained(which is of 3rd degree,except in formic acid:HCOOH)....
i hope u`ve understood....
1No Debosmit, you're totally wrong !!!!
The reaction is similar to acid-base neutralization :
R-COOH + R'MgX → R'H + Mg(RCOO)X
The alkyl group in Grignard Reagent has a partial -ve charge, so it takes the acidic hydrogen present in carboxylic acid, thus forming an alkane !! :)
1i`m sorry....yes i`m totally wrong....it`ll be an acid-base rctn....what i`ve written is in the case of an ester....i dont know what i was thinking....thnx @Razek