Why diff products r formed....in this case.....??

VITEEE Papers › Organic Chemistry questions › Why diff products r formed....in this case.....??

2- Bromo-2-methyl-propane gives two different products with

1. CH3CH2ONa in presence of CH3CH2OH

and

2. CH3CH2OH alone.

WHAT R THESE PRODUCTS AND WHY ARE THEY DIFFERENT WHEN THEY BOTH PRODUCE SAME ANION i.e. CH3CH2O- ?

#Chemistry #Organic Chemistry

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qwerty ·2010-10-18 21:14:27

CH₃CH₂OH is a weak acid.

CH₃CH₂OH â†’ CH₃CH₂O^-+H⁺

dis equilibrium is more towards left. hence conc of CH₃CH₂OH >>CH₃CH₂O^-

hence in ethanol , ethanol will react

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venkateshan ·2010-10-18 23:27:53

in the first case the product will be alkene i.e., 2-methyl prop - 2 - ene and in the second case... it will be ether.. i.e., 2 Ethoxy 2 methyl propane....

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venkateshan ·2010-10-18 23:28:28

i am sry... it will be 2 mythyl propene.. in the 1st case...

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euracle ·2010-10-20 04:59:07

Pls give reason..........

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Basic Integral Calculus Operators Symbols Matrix Cases

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° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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Why diff products r formed....in this case.....??

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