Organic Chemistry - zeiesl method

39

Dr.House ·2009-02-17 04:10:34

wats the question?

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Anirudh Narayanan ·2009-02-17 04:13:28

CH₃I and (CH₃)COH are formed (I hope so [1])

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voldy ·2009-02-17 04:13:33

product likho .

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39

Dr.House ·2009-02-17 04:14:23

ether bond will break................

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voldy ·2009-02-17 04:15:47

so product is t-butyl iodide and methanol ?

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Anirudh Narayanan ·2009-02-17 04:15:52

Strange name......[12]

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Anirudh Narayanan ·2009-02-17 04:17:45

oops, sorry.......I gave the wrong answer......sri u are right da (as usual [1])

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39

Dr.House ·2009-02-17 04:17:55

i think srinath is right.

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vector ·2009-02-17 04:26:23

EVEN I THINK SO

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19

Debotosh.. ·2009-08-14 09:01:29

the S_N2 pathway produces t-butyl iodide and OMe^-....which is a strong base....hence there are chance of occurrences of E₁ reaction that may result in the formation of alkenes...

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voldy ·2009-08-15 18:53:58

good observation but remember this is highly acidic medium . H+ in plenty :)

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