dy/dx=1+y/x
y=vx
dy/dx=v+xdv/dx
xdv/dx=1
dv=dx/x
v=lnx +c
y =xlnx+xC
1=C
y=xlnx+x
1)The solution of the differential equation \frac{dy}{dx}=\frac{x+y}{x} satisfying the condition y(1) =1 is
(1) y=xe(x-1) (2) y=xlnx+x (3) y=ln x + x (4) 2 y = x ln x + x2
dy/dx=1+y/x
y=vx
dy/dx=v+xdv/dx
xdv/dx=1
dv=dx/x
v=lnx +c
y =xlnx+xC
1=C
y=xlnx+x
2) Four species are listed below:
(i) HCO3- (ii) H3O+ (iii) HSO4- (iv) HSO3F
Which one of the following is the correct sequence of their acid strength?
(1) (i) < (iii) < (ii) < (iv) (2) (iii) < (i) < (iv) < (ii) (3) (iv) < (ii) < (iii) < (i) (4) (ii) < (iii) < (i) < (iv)
I think it shud be A
in case of anions HCO3- and HSO4- ..so HSO4- shud be more acidic and among the given species HSO3F is most acidic..
Agree with rocky..it does seem to be 2. NO2 aur kheenchte rahega toh complex unstable ho jaayega.
low energy corresponds to high stability so the one with high stability in the given options shuld have low energy so seems me to be (2) as pritish and rocky has already said abv,[1]