solving C1 and C2 simultaneously we get
x2-2x+1=0 (x-1)2=0
at x=1 y=2 or y=-2
hecne C1and C2 touch each other at exactly two points(1,2) and (1,-2), hence option B
solving C1 and C2 simultaneously we get
x2-2x+1=0 (x-1)2=0
at x=1 y=2 or y=-2
hecne C1and C2 touch each other at exactly two points(1,2) and (1,-2), hence option B