IIT JEE 2009 P1 Q5

IIT JEE 2015 Questions › Past IIT JEE Questions questions › IIT JEE 2009 P1 Q5

The Henry's law constant for the solubility of N₂ gas in water at 298 K is 1.0×10⁵ atm. The mole fraction of N₂ in air is 0.8. The number of moles of N₂ from air dissolved in 10 moles of water at 298 K and 5 atm pressure is
(A)4.0×10^-4
(B)4.0×10^-5
(C)5.0×10^-4
(D)4.0×10^-6

#Miscellaneous #Past IIT JEE Questions

UP 0 DOWN 0 0 7
Post on FacebookPost anonymously?

7 Answers

62

Lokesh Verma ·2009-04-11 20:45:18

[url=http://iitjee2009solutions.targetiit.com]Solution Key with Question Paper of 2009 IIT JEE[/url]

UP 0 DOWN 0
Post on FacebookPost anonymously?

62

Lokesh Verma ·2009-04-12 03:56:40

Answer is (A)

UP 0 DOWN 0
Post on FacebookPost anonymously?

11

mona100 ·2009-04-12 05:49:39

plz give the solution for this question

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

~AjInKyA~ ·2009-04-12 06:04:11

yessssssss
i gueesed n i got right !!
yahooo

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

JOHNCENA IS BACK ·2009-04-12 06:10:03

congos!

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

kamalendu ghosh ·2009-04-12 06:38:15

gochcha

UP 0 DOWN 0
Post on FacebookPost anonymously?

11

Anirudh Narayanan ·2009-04-13 09:12:28

arey, yeh kya hai??? where is the solution??

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω