a = nw2
where w is wavelength.
w = 2an
Now be de-broglie relation,
p = hw
=> p = hn2a
We are given E = p22m
So E = n2h28ma2
E proportional to a-2.
The allowed energy for the particle for a particular value of n is proportional to
A) a-2
B) a-3/2
C) a-1
D) a2
[url=http://iitjee2009solutions.targetiit.com]Solution Key with Question Paper of 2009 IIT JEE[/url]
a = nw2
where w is wavelength.
w = 2an
Now be de-broglie relation,
p = hw
=> p = hn2a
We are given E = p22m
So E = n2h28ma2
E proportional to a-2.