39i am not sure but got b
For a first order raction A-> P the temperature T dependent rate constant k was found to follow the equation log k = -2000/T + 6. The pre exponential factor A and the activatin energy Ea respectively are
A) 1.0x106s-1 and 9.2kJ/mol
B) 6.0 s-1 and 16.6kJ/mol
C) 1.0x106s-1 and 16.6kJ/mol
D) 1.0x106s-1 and 38.3kJ/mol
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62[url=http://iitjee2009solutions.targetiit.com]Solution Key with Question Paper of 2009 IIT JEE[/url]
1damn sure......D is right
we have
logk=logA-Ea/(2.303RT)
comparing
logA=6s
so A=1.0*106s-1
Ea/(2.303RT)=2000
Ea=38.3KJ/mol
