1Answer is 8
The dissociation constant of a substituded benzoic acid at 25 degree C is 10-4
The pH of a 0.001 M solution of its sodium salt is
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10 Answers
62[url=http://iitjee2009solutions.targetiit.com]Solution Key with Question Paper of 2009 IIT JEE[/url]
11@bhaiyya......."The pH of a 0.01 M solution of its sodium salt is " not 0.001
I got pH = 4
Ka = 10-4
c = 0.01 M
α = 0.01
[H+] = 10-4
pH = 4
1Ph of salt of weak acid and strong base
pH=7+.5[pka+log c]
so in this case pKa=4 log c= log .01=-2
pH= 7 + .5{4-2}=7+1=8
1friends u r to consider H+ coming from water also...an acid with pH 8/////////////
never happen.,.,.,.,.,.,.,.,., simple ionic concept,.,consult books
6nishant bhaiya since when did you start asking chemistry questions??:P