1A,B,D
For the reduction of NO3- ion in an aquous solution, E0 is +0.96V. Value of E0 for some metal ions are given below
A) V2+ + 2e- -> V E0=-1.19V
B) Fe3+ + 3e- -> Fe E0=-0.04V
C) Au3+ + 2e- -> Au E0=+1.40V
D) Hg2+ + 2e- -> Hg E0=+.86V
The pair of metals that is oxidized by NO3- in aquous solution is (are)
A) V an Hg
B) Hg and Fe
C) Fe and Au
D) Fe and V
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10 Answers
62[url=http://iitjee2009solutions.targetiit.com]Solution Key with Question Paper of 2009 IIT JEE[/url]
1a,c,d......2000% sure
anyone to challenge....
first balace net reaction then find delta g then come to challlenge
all the bast@rd coaching institutes gave answer as a,b,d......
1so u want to say that Hg is not oxidised by HNO3
and gold is !!
1so chem u better take a look at these
1. with dil nitric acid
6Hg + 8HNO3 -----> 3Hg2(NO3)2 +2NO + 4H2O
clearly Hg is oxidised and NO3- reduced
2. noble metals like gold , platinum , iridium , rhodium etc are not acted upon by nitric acid . however metals dissolve in aqua regia
1dude it is asked for the pair....means when u put the pair of metal in the solution....both should be oxidised.....so write reaction for all three reactions and add delta g...thenu wiil conclude that a,c,d should be the answer.......
1even if u see separately then also for Hg u have E=(3/2)*0.86
AND FOR NO3- E=(3/3)*0.96
SO CLEARRLY HG WILL BE REDUCED
WE MUST BALANCE THE ELECTRONS NAA......