a simple qoestion

≈ 7
6.9...

[H+]=10^{-8}
[H+]w=10^{-7} thus, total H+ions =10^{-7}+10^{-8}=1.1\times10^{-7}
taking -ve log of both sides, pH=6.958

At 25°C

[H⁺]*[OH^-]=10^-14

if x gram-ion/lit is [H⁺]from water

then (x+10^-8)*x=10^-14

x=9.51*10^-8(more accurately)

hence total conc.=9.51*10^-8+10^-8

hence pH=-log(1.051*10^-7)=6.978

here common ion effect is too small to be considerd......

hey rahul...i did the same in exams like u...and got a zero...[17]

i won't do it again...[4]

matlab .. my answer was the best .. [1] .. approximation rules ...

common ion if not considered will give a PH >7 ..

and its impossible since it is an acid..