a simple qoestion

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find the pH of 10^-8 N HCl solution

#Chemistry #Physical Chemistry

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7 Answers

1

ANKIT MAHATO ·2009-03-20 00:09:26

â‰ˆ 7
6.9...

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1

rahul nair ·2009-03-20 00:16:29

[H+]=10^{-8}
[H+]w=10^{-7} thus, total H+ions =10^{-7}+10^{-8}=1.1\times10^{-7}
taking -ve log of both sides, pH=6.958

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13

Ð”Ð²Ò¥Ñ—ÑuÏ now in medical c ·2009-03-20 00:22:56

At 25Â°C

[H⁺]*[OH^-]=10^-14

if x gram-ion/lit is [H⁺]from water

then (x+10^-8)*x=10^-14

x=9.51*10^-8(more accurately)

hence total conc.=9.51*10^-8+10^-8

hence pH=-log(1.051*10^-7)=6.978

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1

rahul nair ·2009-03-20 00:31:24

here common ion effect is too small to be considerd......

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Ð”Ð²Ò¥Ñ—ÑuÏ now in medical c ·2009-03-20 00:39:33

hey rahul...i did the same in exams like u...and got a zero...[17]

i won't do it again...[4]

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1

ANKIT MAHATO ·2009-03-20 02:27:32

matlab .. my answer was the best .. [1] .. approximation rules ...

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skygirl ·2009-03-20 07:58:22

common ion if not considered will give a PH >7 ..

and its impossible since it is an acid..

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